The points (1,1/2) and (3,-1/2) are

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Question Id : 11660 | Context :NIMCET 2024

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Points: $A = (1, \frac{1}{2})$ , $B = (3, -\frac{1}{2})$

Line: $2x + 3y = k$

For A: $2(1) + 3\left(\frac{1}{2}\right) = \frac{7}{2}$
For B: $2(3) + 3\left(-\frac{1}{2}\right) = \frac{9}{2}$

In between the lines $2x + 3y = -6$ and $2x + 3y = 6$ : since $\frac{7}{2}, \frac{9}{2} \in (-6, 6)$
On the same side of $2x + 3y = 6$ : ✔️ True, both values are less than 6
On the same side of $2x + 3y = -6$ : ✔️ True, both values are greater than -6
On the opposite side of $2x + 3y = -6$ : ❌ False, both are on the same side

The correct statements are:

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