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→A=(2x+1)ˆi+(x2−6y)ˆj+(xy2+3z)ˆk
∇⋅→A=2−6+3=−1≠0
Not solenoidal ❌
∇×→A=(2xy)ˆi−(y2)ˆj+(2x)ˆk≠→0
Not conservative ❌
→A is neither conservative nor solenoidal.
Given vector field:
→A=(2x+1)ˆi+(x2−6y)ˆj+(xy2+3z)ˆk
∇⋅→A=2−6+3=−1
The divergence is negative at every point, so →A is a sink field.
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