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Question Id : 11669 | Context :NIMCET 2024

Question

If three distinct numbers are chosen randomly from the first 100 natural numbers, then the probability that all three of them are divisible by both 2 and 3 is
🎥 Video solution / Text Solution of this question is given below:

✔️ Verified Probability

Total numbers divisible by 6 from 1 to 100: 16

\binom{100}{3} = 161700, \quad \binom{16}{3} = 560

Probability: \frac{560}{161700} = \frac{4}{1155}

✅ Final Answer: \boxed{\frac{4}{1155}}

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