Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET
Aspire Study - Best NIMCET Coaching

🎯 Crack NIMCET with Aspire Study

🔹 India's Most Trusted MCA Coaching
💻 Live + Recorded Classes | 👨‍🏫 Expert Faculty
📝 All India Test Series | 🎯 Personal Mentorship

🥈 NIMCET AIR 2: Ayush Garg

🚀 Join Aspire Now

📂 Aspire Study Library


Question Id : 12875 | Context : JEE Main 2022 (25 June Morning Shift)
Let $y = y(x)$ be the solution of the differential equation $(x + 1)y' - y = {e^{3x}}{(x + 1)^2}$, with $y(0) = {1 \over 3}$. Then, the point $x = - {4 \over 3}$ for the curve $y = y(x)$ is :


Aspire Study Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

📲
Ask Your Question or Put Your Review.

loading...