Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET
Aspire Study - Best NIMCET Coaching

🎯 Crack NIMCET with Aspire Study

🔹 India's Most Trusted MCA Coaching
💻 Live + Recorded Classes | 👨‍🏫 Expert Faculty
📝 All India Test Series | 🎯 Personal Mentorship

🥈 NIMCET AIR 2: Ayush Garg

🚀 Join Aspire Now

📂 Aspire Study Library


Question Id : 13051 | Context : JEE Main 2022 (26 July Morning Shift)
If $f(x)= \begin{cases} x+a, & x\le 0\\ |x-4|, & x>0 \end{cases} \quad\text{and}\quad g(x)= \begin{cases} x+1, & x<0\\ (x-4)^{2}+b, & x\ge 0 \end{cases}$ are continuous on $\mathbb{R}$, then $(g\circ f)(2)+(f\circ g)(-2)$ is equal to:


Aspire Study Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

📲
Ask Your Question or Put Your Review.

loading...