Question Id : 13115 |
Context : JEE Main 2022 (28 July Evening Shift)
$
\text{Let } \alpha, \beta \text{ be the roots of the equation } x^{2} - \sqrt{2}x + \sqrt{6} = 0
\text{ and } \dfrac{1}{\alpha^{2}} + 1, ; \dfrac{1}{\beta^{2}} + 1 \text{ be the roots of the equation }
x^{2} + ax + b = 0.
$
$\text{Then the roots of the equation } x^{2} - (a+b-2)x + (a+b+2) = 0 \text{ are :}$
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