\displaystyle \lim_t\to 0\left(1^1/\sin^2 t+2^1/\sin^2 t+*s+n^1/\sin^2 t\righ...

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Question Id : 13164 | Context : JEE Main 2023 (24 January Morning Shift)

$\displaystyle \lim_{t\to 0}\left(1^{\frac{1}{\sin^2 t}}+2^{\frac{1}{\sin^2 t}}+\cdots+n^{\frac{1}{\sin^2 t}}\right)^{\sin^2 t}$ is equal to

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