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Question Id : 13210 | Context : JEE Main 2023 (25 January Evening Shift)
Let $T$ and $C$ respectively be the transverse and conjugate axes of the hyperbola $16x^{2}-y^{2}+64x+4y+44=0$. Then the area of the region above the parabola $x^{2}=y+4$, below the transverse axis $T$ and on the right of the conjugate axis $C$ is:

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