Question Id : 13237 |
Context : JEE Main 2023 (29 January Morning Shift)
Let $x=2$ be a root of the equation $x^{2}+px+q=0$ and define
\[
f(x)=
\begin{cases}
\dfrac{1-\cos\!\big(x^{2}-4px+q^{2}+8q+16\big)}{(x-2p)^{4}}, & x\ne 2p,\\[6pt]
0, & x=2p.
\end{cases}
\]
Then $\displaystyle \lim_{x\to 2p^{+}} \big[\,f(x)\,\big]$, where $[\cdot]$ denotes the greatest integer function, is:
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