Question Id : 13421 |
Context : JEE Main 2023 (11 April Morning Shift)
Let $y = y(x)$ be a solution curve of the differential equation
\[
(1 - x^2 y^2)\,dx = y\,dx + x\,dy.
\]
If the line $x = 1$ intersects the curve $y = y(x)$ at $y = 2$ and the line $x = 2$ intersects the curve $y = y(x)$ at $y = \alpha$,
then a value of $\alpha$ is:
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