Question Id : 13439 |
Context : JEE Main 2023 (11 April Evening Shift)
If the $1011^{\text{th}}$ term from the end in the binomial expansion of
\(\left(\dfrac{4x}{5}-\dfrac{5}{2x}\right)^{2022}\) is \(1024\) times the
$1011^{\text{th}}$ term from the beginning, then \(|x|\) is equal to:
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