he degree of the differential equation
$\left[1 + \left(\dfrac{dy}{dx}\right)^2\right]^{3/2} = \dfrac{d^2y}{dx^2}$ is:
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**Solution:**
To find the degree, remove the fractional exponent by squaring both sides:
$\left[\,1 + \left(\dfrac{dy}{dx}\right)^2\right]^3 = \left(\dfrac{d^2y}{dx^2}\right)^2$
Now the equation is polynomial in derivatives, and the highest order derivative is $\dfrac{d^2y}{dx^2}$ appearing as a square term.
Therefore,
**Degree = 2**
$\boxed{\text{Answer: (D) 2}}$