Question Id : 14331 |
Context : JEE Main 2024 (4 April Morning Shift)
If the solution $y = y(x)$ of the differential equation
$(x^{4}+2x^{3}+3x^{2}+2x+2)\,dy-(2x^{2}+2x+3)\,dx=0$
satisfies $y(-1)=-\dfrac{\pi}{4}$, then $y(0)$ is equal to:
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