Question Id : 14524 |
Context : JEE Main 2024 (9 April Evening Shift)
Consider the line $L$ passing through the points $(1,2,3)$ and $(2,3,5)$.
The distance of the point $\left(\dfrac{11}{3},\dfrac{11}{3},\dfrac{19}{3}\right)$ from the line $L$ along the line
$\dfrac{3x-11}{2}=\dfrac{3y-11}{1}=\dfrac{3z-19}{2}$ is equal to:
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