The number of arrangements of the letters of the word BANANA in which two N’s do not appear adjacently is …
🎥 Video solution / Text Solution of this question is given below:
Total letters = 6 (B, A, N, A, N, A).
Total arrangements = $\dfrac{6}{32} = 60$.
If two N’s are together, treat NN as one letter → letters = (NN, B, A, A, A).
Arrangements = $\dfrac{5}{3} = 20$.
Hence, required = $60 - 20 = 40$.