The points $A(12,8)$, $B(-2,6)$ and $C(6,0)$ are the vertices of …
🎥 Video solution / Text Solution of this question is given below:
$AB^{2}=14^{2}+2^{2}=200,\ BC^{2}=(-8)^{2}+6^{2}=100,\ CA^{2}=(-6)^{2}+(-8)^{2}=100$.
Since $BC=CA$ the triangle is isosceles, and $BC^{2}+CA^{2}=AB^{2}$ ⇒ right-angled at $C$.