Two dice are thrown. The probability that the sum of the numbers on two dice is 7 is …
🎥 Video solution / Text Solution of this question is given below:
Total outcomes = $6 \times 6 = 36$.
Favorable outcomes for sum = 7 are $(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)$ → 6 outcomes.
Probability $= \dfrac{6}{36} = \dfrac{1}{6}$.