JEE Main 2019 (11 January Morning Shift)

Question

If $y(x)$ is the solution of the differential equation $\dfrac{dy}{dx}+\left(\dfrac{2x+1}{x}\right)y=e^{-2x},\ x>0,$ where $y(1)=\dfrac{1}{2}e^{-2}$, then

Accepted Answer

$y(x)$ is decreasing in $\left(\dfrac{1}{2},1\right)$

Answer

$y(\log_e 2)=\log_e 4$

Answer

$y(x)$ is decreasing in $(0,1)$

Answer

$y(\log_e 2)=\dfrac{\log_e 2}{4}$

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