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Question Id : 15905 | Context : JEE Main 2018 (15 April Morning Shift)
Let y = y(x) be the solution of the differential equation ${{dy} \over {dx}} + 2y = f\left( x \right),$

where $f\left( x \right) = \left\{ {\matrix{ {1,} & {x \in \left[ {0,1} \right]} \cr {0,} & {otherwise} \cr } } \right.$

If y(0) = 0, then $y\left( {{3 \over 2}} \right)$ is :


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