Question Id : 17933 |
Context : JEE Main 2026 (21 January Evening Shift)
If
$\displaystyle \left(\frac{1}{^{15}C_0} + \frac{1}{^{15}C_1}\right)\left(\frac{1}{^{15}C_1} + \frac{1}{^{15}C_2}\right)\cdots\left(\frac{1}{^{15}C_{12}} + \frac{1}{^{15}C_{13}}\right) = \frac{\alpha^{13}}{^{14}C_0\cdot ^{14}C_1\cdots ^{14}C_{12}}$
then $30\alpha$ is equal to ______.
🎥 Video solution / Text Solution of this question is given below: