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Question Id : 17939 | Context : JEE Main 2026 (22 January Morning Shift)
Let $f(x) = x^{2025} - x^{2000},; x \in [0,1]$ and maximum value of the function $f(x)$ in the interval $[0,1]$ be $\left(\frac{80}{81}\right)^{n}$, then $n$ is equal to:

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