Question Id : 18031 |
Context : JEE Main 2026 (23 January Evening Shift)
If the solution curve $y = f(x)$ of the differential equation
$(x^2 - 4)y' - 2xy + 2x(4 - x)^2 = 0,; x > 2$,
passes through the point $(3, 15)$, then the local maximum value of $f$ is ______.
🎥 Video solution / Text Solution of this question is given below: