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Question Id : 18036 | Context : JEE Main 2026 (24 January Morning Shift)
If the function $f(x)=\dfrac{e^x\left(e^{\tan x}-1\right)+\ln(\sec x+\tan x)-x}{\tan x-x}$ is continuous at $x=0$, then the value of $f(0)$ is equal to:

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