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Question Id : 18049 | Context : JEE Main 2026 (24 January Morning Shift)
Let $S=\frac{1}{25!}+\frac{1}{3!23!}+\frac{1}{5!21!}+\cdots$ (13 terms) If $13S=\frac{2^k}{n!}$, then $n+k$ is equal to:

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