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Question Id : 4003 | Context :NIMCET 2019

Question

Ten points are marked on a straight line and eleven points are marked on another straight line. How many triangles can be constructed with vertices from among the above points?
🎥 Video solution / Text Solution of this question is given below:

We can get the triangles in two different ways.

Taking two points from the line having 10 points

(in 10C2 ways, i.e., 45 ways) and one point from the line consisting of 11 points (in 11 ways).

So, the number of triangles here is 45×11=495.

Taking two points from the line having 11 points (in 11C2, i.e., 55 ways) and one point from the line consisting of 10 points (in 10 ways), the number of triangles here is 55×10=550

Total number of triangles, =495+550

=1,045 triangles

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Ask Your Question or Put Your Review.
Shrashti Mandloi-pic
Shrashti Mandloi ,
Commented Jul 23 , 2021
How to solve this question, I don't understand, please explain.