[Video Solution] For t\in(0,2π), if \triangle ABC is an equilateral triangle with vertices A(\... | ASPIRE STUDY

Name: [Video Solution] For t\in(0,2π), if \triangle ABC is an equilateral triangle with vertices A(\... | ASPIRE STUDY
Uploaded: 2026-10-09T07:28:20+00:00
Description: For t\in(0,2π), if \triangle ABC is an equilateral triangle with vertices A(\sin t,-\cos t), B(\cos t,\sin t) and C(a,b) such that its orthocentre lies on a circle with centre \left(1,\tfrac13\right), then (a^2-b^2) is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.

For t\in(0,2π), if \triangle ABC is an equilateral triangle with vertices A(\sin t,-\cos t), B(\cos t,\sin t) and C(a,b) such that its orthocentre lies on a circle with centre \left(1,\tfrac13\right), then (a^2-b^2) is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-10-09T07:28:20+00:00 Thumbnail: Open Page: https://www.myaspirestudy.com/library/video/13106/for-t-in-0-2-if-triangle-abc-is-an-equilateral-triangle-with-vertices-a

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