[Video Solution] Let S_1 = \ z_1 \in \mathbbC : |z_1 - 3| = \tfrac12 \ and S_2 = \ z_2 \in \... | ASPIRE STUDY

Name: [Video Solution] Let S_1 = \ z_1 \in \mathbbC : |z_1 - 3| = \tfrac12 \ and S_2 = \ z_2 \in \... | ASPIRE STUDY
Uploaded: 2026-10-10T10:09:37+00:00
Description: Let S_1 = \ z_1 \in \mathbbC : |z_1 - 3| = \tfrac12 \ and S_2 = \ z_2 \in \mathbbC : |z_2 - |z_2 + 1|| = |z_2 + |z_2 - 1|| \. Then, for z_1 \in S_1 and z_2 \in S_2, the least value of |z_2 - z_1| is : | Watch the step-by-step video solution for this NIMCET PYQ.

Let S_1 = \ z_1 \in \mathbbC : |z_1 - 3| = \tfrac12 \ and S_2 = \ z_2 \in \mathbbC : |z_2 - |z_2 + 1|| = |z_2 + |z_2 - 1|| \. Then, for z_1 \in S_1 and z_2 \in S_2, the least value of |z_2 - z_1| is : | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-10-10T10:09:37+00:00 Thumbnail: Open Page: https://www.myaspirestudy.com/library/video/13111/let-s-1-z-1-in-mathbbc-z-1-3-tfrac12-and-s-2-z-2-in

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