[Video Solution] For a triangle ABC, let \vecp = \overrightarrowBC,; \vecq = \overrightarrowCA... | ASPIRE STUDY

For a triangle ABC, let \vecp = \overrightarrowBC,; \vecq = \overrightarrowCA and \vecr = \overrightarrowBA. If |\vecp| = 2√3,; |\vecq| = 2 and \cosθ = 1/√3, where θ is the angle between \vecp and \vecq, then|\vecp*(\vecq-3\vecr)|^2 + 3|\vecr|^2 is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.