[Video Solution] Let P(10,2√15) be a point on the hyperbola \dfracx^2a^2-\dfracy^2b^2=1, whose... | ASPIRE STUDY

Name: [Video Solution] Let P(10,2√15) be a point on the hyperbola \dfracx^2a^2-\dfracy^2b^2=1, whose... | ASPIRE STUDY
Uploaded: 2026-10-07T03:03:00+00:00
Description: Let P(10,2√15) be a point on the hyperbola \dfracx^2a^2-\dfracy^2b^2=1, whose foci are S and S'. If the length of its latus rectum is 8, then the square of the area of \Delta PSS' is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.

Let P(10,2√15) be a point on the hyperbola \dfracx^2a^2-\dfracy^2b^2=1, whose foci are S and S'. If the length of its latus rectum is 8, then the square of the area of \Delta PSS' is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-10-07T03:03:00+00:00 Thumbnail: Open Page: https://www.myaspirestudy.com/library/video/17971/let-p-10-2-15-be-a-point-on-the-hyperbola-dfracx-2a-2-dfracy-2b-2-1-whose

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