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Let I(x) = ∫ \dfrac3dx(4x+6)√4x^2 + 8x + 3 and I(0) = \dfrac√34 + 20. If I\left(\dfrac12\right) = \dfraca√2b + c, where a,b,c \in \mathbbN, \gcd(a,b)=1, then a + b + c is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.