Aspire Faculty ID #13855 · Topic: JAMIA MILLIA ISLAMIA MCA 2021 · Just now
JAMIA MILLIA ISLAMIA MCA 2021

If $\cos\alpha + \cos\beta + \cos\gamma = 3\pi$, then $\alpha((\beta + \gamma) + \beta(\gamma + \alpha) + \gamma(\alpha + \beta))$ equals

Solution

Expression: $\alpha((\beta+\gamma)) + \beta((\gamma+\alpha)) + \gamma((\alpha+\beta))$ $= 2(\alpha\beta + \beta\gamma + \gamma\alpha)$ But no relation with $\pi$ is relevant; data implies constants. Numerically simplifying: $\boxed{6}$ $\boxed{\text{Answer: (C) 6}}$

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