Aspire Faculty ID #14061 · Topic: JAMIA MILLIA ISLAMIA MCA 2019 · Just now
JAMIA MILLIA ISLAMIA MCA 2019

The points of extremum of the function $f(x) = \displaystyle \int_0^x e^{t^2} (1 - t^2)\,dt$ are:

Solution

$f'(x) = e^{x^2}(1 - x^2)$. Setting $f'(x) = 0 \Rightarrow 1 - x^2 = 0 \Rightarrow x = \pm 1$.

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