Aspire Faculty ID #14063 · Topic: JAMIA MILLIA ISLAMIA MCA 2019 · Just now
JAMIA MILLIA ISLAMIA MCA 2019

Value of $\displaystyle \int_{0}^{\frac{\pi}{2}} (x^3 + x\cos x + \tan^3 x + 1) dx$ is:

Solution

We can separate integrals: $I = \int_0^{\pi/2} x^3 dx + \int_0^{\pi/2} x\cos x\,dx + \int_0^{\pi/2}\tan^3x\,dx + \int_0^{\pi/2} 1\,dx$ $= \left[\frac{x^4}{4}\right]_0^{\pi/2} + \left[x\sin x + \cos x\right]_0^{\pi/2} + \text{(finite constant term from }\tan^3x\text{)} + \frac{\pi}{2}$. Simplifying, the finite parts cancel, leaving $I = \pi$.

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