Aspire Faculty ID #15100 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

The complex numbers $\sin x + i\cos 2x$ and $\cos x - i\sin 2x$ are conjugate to each other for A. $x = n\pi$ B. $x = 0$ C. $x = (n + \tfrac{1}{2})\pi$ D. No value of $x$

Solution

Conjugates ⇒ $\cos 2x = \sin x \Rightarrow x = (n + \tfrac{1}{2})\pi.$

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