Aspire Faculty ID #15261 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

$\displaystyle \int_{1}^{x}(1+\log t)^{2}\,dt$ is equal to …

Solution

Let $y=1+\log t \Rightarrow t=e^{y-1}$, $dt=e^{y-1}dy$. After simplification: $x((1+\log x)^{2}-2(1+\log x)+2)-1$.

Previous 10 Questions — JAMIA MCA 2016

Nearest first

Next 10 Questions — JAMIA MCA 2016

Ascending by ID
Ask Your Question or Put Your Review.

loading...