Aspire Faculty ID #15267 · Topic: JAMIA MCA 2016 · Just now
JAMIA MCA 2016

If $\cos\theta + \sec\theta = 3$, then $\cos^{2}\theta + \sec^{2}\theta$ is …

Solution

Let $\cos\theta = x \Rightarrow \sec\theta = \dfrac{1}{x}$. So, $x + \dfrac{1}{x} = 3 \Rightarrow x^{2} + \dfrac{1}{x^{2}} = (x + \dfrac{1}{x})^{2} - 2 = 9 - 2 = 7.$ Hence $\cos^{2}\theta + \sec^{2}\theta = 7.$

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