Aspire Faculty ID #16588 · Topic: NIMCET 2008 · Just now
NIMCET 2008

If $x$ and $y$ are the two digits of the number $565xy$ such that the number is divisible by $80$, then $x+y$ equals

Solution

For divisibility by $80$, the last two digits must be divisible by $80$. Possible ending is $80$. So $x=8,\ y=0 \Rightarrow x+y=8$. But $y$ must be a digit, so $x+y=8+0=8$,

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