Aspire Faculty ID #18044 · Topic: JEE Main 2026 (24 January Morning Shift) · Just now
JEE Main 2026 (24 January Morning Shift)

Let $S={z\in\mathbb{C}:\left|\frac{z-6i}{z-2i}\right|=1 \text{ and } \left|\frac{z-8+2i}{z+2i}\right|=\frac{3}{5}}$ Then $\sum_{z\in S}|z|^2$ is equal to:

Solution

$\left|\frac{z-6i}{z-2i}\right|=1 \Rightarrow y=4$

$\left|\frac{z-8+2i}{z+2i}\right|=\frac{3}{5}$

$\Rightarrow x^2+y^2-25x+4y+104=0$

Substitute $y=4$

$x=17,; 8$

$z=17+4i,; 8+4i$

$\sum |z|^2 = 17^2+4^2 + 8^2+4^2 = 385$

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