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Let the eccentricity of the ellipse x^2 + a^2y^2 = 25a^2 be b times the eccentricity of the hyperbola x^2 - a^2y^2 = 5, where a is the minimum distance between the curves y = ex and y = logex. Then a^2 + 1 \over b^2 is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.