[Video Solution] Let x=2 be a root of the equation x^2+px+q=0 and define \[ f(x)= \begincases ... | ASPIRE STUDY

Let x=2 be a root of the equation x^2+px+q=0 and define \[ f(x)= \begincases \dfrac1-\cos\!\big(x^2-4px+q^2+8q+16\big)(x-2p)^4, & x\ne 2p,\\[6pt] 0, & x=2p. \endcases \] Then \displaystyle \lim_x\to 2p^+ \big[\,f(x)\,\big], where [*] denotes the greatest integer function, is: | Watch the step-by-step video solution for this NIMCET PYQ.