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If the local maximum value of the function f(x)=\left(\dfrac√3e2\sin x\right)^\sin^2x,; x\in\left(0,\dfracπ2\right), is \dfracke, then \left(\dfracke\right)^8+\dfrack^8e^5+k^8 is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.