Aspire Faculty ID #14057 · Topic: JAMIA MILLIA ISLAMIA MCA 2019 · Just now
JAMIA MILLIA ISLAMIA MCA 2019

Number of points at which the function $f(x) = \min(|x|, |x+1|, |x-4|)$ is not differentiable is:

Solution

Each $|x|$ term is non-differentiable at the point where its argument = 0. Points: $x = 0, -1, 4$.

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