Aspire Faculty ID #16597 · Topic: NIMCET 2008 · Just now
NIMCET 2008

Substitutes digits for the letters to make the following relation true
  S T I L L  
+ W I T H I N  
---------------  
  L I M I T S  
Note that the leftmost letter can‟t be zero in any word. Also, there must be a one-to-one mapping
between digits and letters, e.g. if you substitute 3 for the letter S, no other letter can be 3 and all
-8-
other S in the puzzle must be 3.

Solution

From the column addition,

Since the 5th column gives $S+c_4=10c_5$ and $S\neq0$, we must have $S=9,\ c_4=1,\ c_5=1$.

Then $H$ cannot be $9$, so the only valid case is $H=0$.

From last column $W+c_5=L \Rightarrow L=W+1$.

From units column $L+N=S \Rightarrow N=9-L$.

Solving remaining constraints gives:

$S=9,\ T=7,\ I=1,\ L=6,\ W=5,\ H=0,\ N=3,\ M=4$

So,
$STILL=97166$
$WITHIN=517013$
$LIMITS=614179$

Check:
$97166+517013=614179$ ✅

Final Answer:
Correct relation is $97166+517013=614179$.
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